a^2-5(1+2)=a^2-15

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Solution for a^2-5(1+2)=a^2-15 equation:



a^2-5(1+2)=a^2-15
We move all terms to the left:
a^2-5(1+2)-(a^2-15)=0
We add all the numbers together, and all the variables
a^2-(a^2-15)-53=0
We get rid of parentheses
a^2-a^2+15-53=0
We add all the numbers together, and all the variables
-38!=0
There is no solution for this equation

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